![log_pa=b\ \ \ \Leftrightarrow\ \ \ p^b=a\\\\loga+logb=log(a\cdot b)\ \ \ \Rightarrow\ \ \ D:\ a0\ \ \ and\ \ \ b0\\ ----------------------------- \\log(5x)+log(x-1)=2\ \ \ \Rightarrow\ \ \ D:\ 5x0\ \ \ and\ \ \ x-10\\.\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ x0\ \ \ and\ \ \ \ \ \ \ \ x1\\.\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ D=(1;+\infty)\\\\log[5x\cdot(x-1)]=2\ \ \ \Leftrightarrow\ \ \ 5x(x-1)=10^2](/tpl/images/0748/6287/b4b84.png)
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