Can i get the answer for the questions at the bottom

27)

Equation of the existing water pipe's line

a) slope, m = rise / run = Δy / Δx = 3/2

b) y-intercept, b = 3

equation: y = mx + b = (3/2)x + 3

Equation of the new water pipe's line

slope, m = - 1 / (slope of the perpendicular line) = - 1 / (3/2) = - 2/3

point (0,2)

=> y - 2 = (-2/3) (x - 0) => y = (-2/3)x + 2 < equation of the new pipe

28)

two parallel lines have the same slope =>

slope, m = rise / run = Δy / Δx = [4 - 0] / [11 - 8] = 4 / 3

point (4,5) => y - 5 = (4/3) (x - 4)

=> y = (4/3)x - 16/3 + 5 = (4/3)x - 1/3

y = (4/3)x - 1/3  <--- equation of the new bike path