(3h-2m)(2h+m) multiple

If you want to multiply 2 binomials, take each term in the first set of parentheses and multiply it to every term in the second set of parentheses:
3h*(2h+m) = 3h^2+3hm
-2m*(2h+m) = -4hm-2m^2
Combine like terms: (3hm-4hm)
3h^2-hm-2m^2

Bis the right answer

In all honesty, there really is no “work” per say to show. mainly it’s just using the process of elimination. the question is asking which domain(s) would be the most appropriate for the function c(n). n is the number of observed vehicles so right away, 1, 2, and 3 can be eliminated.why? 1, 2 start in the negatives and therefore it is impossible to observe negative cars. so, #4 would be the best answer to the given problem.