Part a which projectile spends more time in the air, the one fired from 30∘ or the one fired from 60∘? which projectile spends more time in the air, the one fired from 30 or the one fired from 60? the one fired from 30∘ they both spend the same amount of time in the air. the one fired from 60∘

The correct answer is the One fired from from 60° . This is because the projectile fired from 60° has a greater vertical velocity compared to the one fired from 30° and therefore spends more time on air. Vertical velocity is the velocity of a body as it moves upwards, it is normally affected by the gravitational acceleration, however it is not affected by the horizontal velocity.

The time it takes for the object in projectile motion to be in air is calculated through the equation, 

             time of flight = 2v₀sinθ/g

If all else are equal except for θ then, we compare their sin values.
 sin(30°) = 0.5
 sin(60°) = 0.866

Since the value of sin60° is greater than the value of sin30° then, projectile motion fired at an angle of 60° will spend more time in air. 

The answer is the last choice. 

Idon’t know but you’ll figure it out