Find the equation of the tangent line at the point (1, 6). for y = 4 + 4x2 - 2x3.

The tangential line at a certain point is just the derivative so.
. At the point (1,6) we plug the x value in and get the slope at the point (y ' = 2)

The tangential line at that point is
y - 6 = 2(x - 1)     (this is the answer)