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Mathematics, 03.08.2019 17:40 restra06

Find the value(s) of x such that f''(x)=0  f_{(x)=} \frac{x}{ x^{2} +2} using \frac{dy}{dx} = \frac{u'v-uv'}{ v^{2} }

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Find the value(s) of x such that f''(x)=0 [tex] f_{(x)=} \frac{x}{ x^{2} +2} using \frac{dy}{dx} = \...
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