Arectangle has a length of 4 times the width minus 7.the perimeter is 136.find the width and the length.

Let the width be x

Therefore Length will be 4x - 7

Formula for perimeter of rectangle is:

2L + 2w = P  (where L is length, w is width and P is perimeter.)

2(4x -7) + 2 (x) = 136

8x -14 + 2x  = 136

8x + 2x  = 136 + 14

       10x  = 150

            x = 150/10

             x = 15

The width is 15

therefore the length will be : 4(15) -7 →  60 - 7 =  53

The length is 53

the answer is 8/21

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