Answers: 1
and the second one is 
;; it's tricky because the denominators aren't the same. You have to factor all of the denominators and multiply only the expressions that the other numbers are missing.
. Multiply 
to the left side and 
to the right, since those are the values the denominator is missing. This results in 
. When simplified, the answer would be 
. Like the first one, multiply the missing value to the right side, 
, and simplify, resulting in 
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[tex]\frac{1}{x^2+3x-4} - \frac{1}{x^2-3x+2}[/tex][tex]\frac{ 3}{x^2-4} - \frac{x+5}{x+2}[/tex]...
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