The measure of the seven angles in a nonagon measure 138, 154, 145, 132, 128, 147 and 130. if the two remaining angles are equal in measure, what is the measure of each angle

A polygon is any figure sided with three sides and above such that triangle (3) is the smallest polygon. A nonagon is a polygon with 9 sides. To get the sum of interior angles of a polygon we use the formula;
(n-2) 180 or (n-4)90 where n is the number of sides.
Therefore, for a nonagon the sum of interior angles = (9-2) 180 = 1260 degrees
If we add all the angles we should get 1260, considering the remaining angles to be each x
Thus 138+154 +145 +132 +128 +147 +130 + x +x =1260
                             = 974 + 2x = 1260
                             = 2x = 286
                             = 143
 therefore, each of the other angles was 143 

Since the two remaining angles are equal in measure, the measure of each angle is 143°.

Let the unknown angles be a.

Given the following data:

First angle = 138°Second angle = 154°Third angle = 145°Fourth angle = 132°Fifth angle = 128°Sixth angle = 147°Seventh angle = 130°

To find the two remaining angles:

A nonagon is a type of polygon that comprises nine (9) sides.

First of all, we would determine the sum of the interior angles of a nonagon by using the following formula:

Where:

n is the number of sides of a polygon.

For a nonagon:

n = 9

Nonagon = 1260°

Substituting the given parameters into the formula, we have;

a = 143°

Read more: link

I’m not sure i’m sorry