Complete the paragraph proof. given: ∠abr and ∠acr are right angles ab ≅ bc bc ≅ ac prove: bisects ∠bac it is given that ∠abr and ∠acr are right angles, ab ≅ bc and bc ≅ ac since they contain right angles, △abr and △acr are right triangles. the right triangles share hypotenuse ar, and reflexive property justifies that ar ≅ ar. since ab ≅ bc and bc ≅ ac, the transitive property justifies ab ≅ ac. now, the hypotenuse and leg of right △abr is congruent to the hypotenuse and the leg of right △acr, so △abr ≅ △acr by the hl congruence postulate. therefore, by cpctc, and bisects ∠bac by the definition of bisector.

The answer is <BAR ≅<CAR :)

∠BAR=∠CAR [∴ΔABR≅ΔACR]

Step-by-step explanation:

In ΔABR and ΔACR

AB=AC=X [ ∴AB≅BC, and BC≅AC, So AB≅AC]

∠ABR = ∠ACR [ each being 90°]

AR is common.

ΔABR ≅ ΔACR [ RHS]

RHS means if in two right triangles hypotenuse and one side of a triangle is equal to hypotenuse and other side then the two triangles are congruent.

So ,∠BAC is bisected.

i.e, ∠BAR=∠CAR [ CPCT ]

Hence proved.

- both graphs increase on their domain.

- the graphs of both functions have the same x-intercept.

- neither graph has a y-intercept.

area of rectangle a is 2 times that of rectangle b that means 2x+x =   36cm^2

3x = 36cm ^2

x = 36/3

x= 12cm^2

and 2x = 24cm^2

now side of square = are divided by sides = 36/4 = 6cm

that means length of rectangle a and b is 6cm too

now for rectangle a,

l*b = area

= 6*y=24

y=24/6 = 4

therefore dimensions of rectangle a are- length = 6cm, breadth = 4cm

and for rectangle b, length = 6cm and breadth = 6-4 = 2cm.

hope this .