Given: δавс, m∠acb = 90° cd ⊥ ab , m∠acd = 60° bc = 6 cm find cd, area of δabc

CD = 3√3 cm

Area  ΔABC =18cm²

Step-by-step explanation:

the angle  < ACB =90°

<ACD =60° therefore <BCD =30°

cos 30°= x/6

x= 3√3 cm

Area  ΔABC =1/2×base×height

the  ΔABC is a 45 45 90 triangle

: AC =6√3 cm

ΔABC = 1/2×6√3×6

ΔABC =18√3 cm²

10% of increase is the final answer! : )

hope this !

step-by-step explanation:

d = distance between moon and sun, which in this problem is the hypotenuse of a right triangle.  

the distance y is the side opposite to angle x in the right triangle.   use the definition of the sine function from basic trigonometry.

sin(x) = y/d ⇒

d = y/sin(x)