Agolf ball is hit from the ground, and its height in feet above the ground is modeled by the function h(t) = -16t^2 + 180t, where t represents the time in seconds after the ball is hit. how long is the ball in the air

The time that the ball is in the air is 2x the time that it takes to reach the maximum value.

In order to find the time at the max value you use the equation -b/2a where b is the value attached to the t and a is the value attached to t^2. 

therefore, the time at the max value is -180/(2)(-16)=5.625 seconds

Total time= (5.625)(2)=11.25

Ithink the answer is $2.10