Finf the exact value of sin a and cos a where a = 9 and b = 10 and < c is a right angle

sin A = 0.6666666667 ≈ 0.67

cos A = 0.7407407407  ≈ 0.74

Step-by-step explanation:

The triangle above is a right angle triangle . Angle C is the angle 90°. we can use the cosine law for triangle to solve for side c.

c² = a² + b² - 2ab.cos(C)

a = 9

b = 10

C = 90°

c² = 9² + 10² - 2 × 9 × 10 cos( 90)

c² = 81 + 100 - 180 × 0

c² = 181

c = √181

c = 13.45362405  ≈ 13.5

Using sine rule

a/sin A = b/sin B = c/sin C

a = 9

b = 10

c = 13.5

C = 90°

9/sin A = 13.5/sin 90°

13.5 sin A = 9 × sin 90°

13.5 sin A = 9

sin A = 9/13.5

sin A = 0.6666666667

Use SOHCAHTOA principle to find cos A

cos A = b/c

cos A =  10/13.5

cos A = 0.7407407407

5x+40

5(x + 8)

7x - 49

7(x - 7)

18x + 9

9(2x + 1)

15x - 10

5(3x - 2)

step-by-step explanation:

for number one all you have to do is factor 5 out of 5x + 40

for number 2 factor 7 out of 7x - 49

for number three factor 9 out of 18x + 9

for number four factor 5 out of 15x - 10