Which of the following is a polynomial function in standard form with zeros at –8, –1, and 3?

a) f(x) = (x + 8)(x + 1)(x – 3)
b) f(x) = x^3 – 6x^2 – 19x + 24
c) f(x) = x^3 + 6x^2 – 19x – 24
d) f(x) = (x – 8)(x – 1)(x + 3)

Option: C is the correct answer.

The polynomial in standard form is:

   C)    

The standard form of a equation of a polynomial is written as :

  We arrange the terms from least to highest power of x.

We know that if a polynomial has roots as:

a, b and c then the equation of the polynomial is given by:

Here we  have: a= -8 , b= -1 and c=3

Hence, the equation of the circle is given  by:

which on expanding gives:

Hence, the standard equation of the polynomial is:

im a goose

step-by-step explanation:

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true? is that what you're asking or do you mean something else?