Afundraising dinner is being held. one person buys 8 childrens tickets and 1 adult ticket and pays $16.50. another person buys 6 childrens tickets and 1 adult ticket and pays $14.00. how much are childrens tickets and adults tickets? a. children's tickets=$6.50; adult's tickets=$1.50 b. children's tickets=$1.25; adult's tickets=$15.25 c. children's tickets=$1.25; adult's tickets=$6.50 d. not enough information is provided. plz answer as soon as possible, will give !

Let an adult ticket cost a.
Let a child ticket cost c.

"One person buys 8 children's tickets and 1 adult ticket and pays $16.50."

8c + a = 16.5

"Another person buys 6 children's tickets and 1 adult ticket and pays $14.00."

6c + a = 14

We have a system of equations.

8c + a = 16.5
6c + a = 14

Subtract the second equation from the first equation.

2c = 2.5

c = 1.25

Now substitute 1.25 for c in the first equation and solve for a.

8(1.25) + a = 16.5

10 + a = 16.5

a = 6.5

An adult ticket costs $6.50, and a child ticket costs $1.25.

Ithink the answer may be -7 by when dividing both sides by -3