Show the region which satisfies simultaneously the inequalities 2x+3y≤8, x-2y≥-3, x≥0, y≥0

The first thing you should do is graph the following lines
 2x + 3y = 8
 x-2y = -3
 x = 0
 y = 0
 After you have graphed them, you should proceed to evaluate points in the xy plane that meet the following restrictions:
 2x + 3y≤8, x-2y≥-3, x≥0, y≥0
 The resulting region is the region "R" shown in the attached graph.

The answer is all about the number 4

The answer is b: step 2.