Find the equation of a line that passes through the point (2,1) and has a gradient of 2 leave your answer in the form of y=mx+c

y= 2x - 3

Step by step solution:

Y = mx + c  

Where

y= y coordinate

m = gradient (it is known as steepness of the slope)

x= x coordinate  

c = y intercept  

m = 2

c = ?

x = 2

y = 1

Substitute the values in the above equation  

y = mx + c  

1 = 2 (2) + c

1 = 4 + c

1 – 4 = c

-3 = c

y = 2x - 3

y=3n + 1

step-by-step explanation:

this is wrong because it says the second number is one less and i added one instead

6: 07 is your answer

step-by-step explanation: