Use the three steps to solve the problem. with a certain tail wind a jet aircraft arrives at its destination, 1,890 miles away, in 3 hours. flying against the same wind, the plane makes the return trip in 3 3/8 hours. find the wind speed and the plane's airspeed. {wind speed is ? a0 mph, airspeed is ? a1 mph}

The wind's speed is  35 miles/hour

The aircraft's speed is 595 miles/hour.

Step-by-step explanation:

Given: Distance =1890 miles

Let speed of aircraft be 'u' and the speed of the wind be 'v'.

With a certain tail wind a jet aircraft arrives at its destination, 1,890 miles away, in 3 hours.

∴ the relative speed = u+v=

⇒ (u+v)=1890/3=630................(1)

Flying against the same wind, the plane makes the return trip in 3 3/8 (27/8)hours.

⇒ ∴ the relative speed = u-v=

⇒u-v=.................(2)

addind (1) and (2),we get

2u=630+560=1190

⇒u=1190/2=595 miles/hour

Substitute u=595 in (1),we get

⇒595+v=630

⇒v=630-595=35 miles/hour.

Therefore ,the wind's speed is v = 35miles/hour

the aircraft's speed is u = 595 miles/hour.

b

step-by-step explanation:

given

- 2 (3x + 12y - 5 - 17x - 16y + 4 )

simplify the parenthesis by collecting like terms

= - 2 (- 14x - 4y - 1) ← distribute the parenthesis by - 2

= 28x + 8y + 2 → b

you cant answer this dummy

step-by-step explanation: