Ineed to know the minimum number of straight fences needed to divide the 4 pigs such that each pig has its own pen? what number of pigs could they individually pen? demonstrate how the fences could be individually divided and how many pigs can be accommodated. justify your solutions. what number of pigs can be accommodated if they built 6straight fences? what is the largest number of pigs that can have an individual pen?

the direct variation says that:

then the equation is of the form is given by:

            where k is the constant variation.

from the given table:

consider any value of x and m(x)=y

x = 2 and m(x)=y = 3

substitute these value in [1]; we have;

divide both sides by 2 we get;

⇒

check:

put x = -1 and m(x) = -1.5

substitute in the equation:

-1.5 = -1.5                   true

therefore, the function m(x) represents a direct variation

graph of this function as shown below:

50*10 is greater

step-by-step explanation:

if you add the zero from 10 to 50, it will give you a bigger number.