Every 5 years in march the population of a certain town is recorded in 1995 the town had a population of 4,500 people. from 1995-2000 the population increased by 15% from 2000-2005 the population decreased by 4% what was the towns population in 2005?

7379.

Step-by-step explanation:

We have been given that every 5 years in march the population of a certain town is recorded in 1995 the town had a population of 4,500 people.

From 1995-2000 the population increased by 15%.

Let us find the population in 2000 using exponential growth formula.

, where,

a = Initial amount or value,

r = Growth rate in decimal form.

Let us convert our given rate in decimal form.

To find the population in year 2005 we will use exponential decrease function.

, where,

a = Initial amount or value,

r = Decay rate in decimal form.

Let us convert our given rate in decimal form.

Since we can not have 0.938 of a person, therefore, the population of town was 7379 in 2005.

option 1 is correct.

step-by-step explanation:

y varies inversely with x and constant of variation is 4

the equation will be:

y = k/x

where k =4 so,

y = 4/x

if we put values of x of option 1 in the above equation and find values of y

y = 4/-2 => y =-2

y = 4/-1 => y = -4

y = 4/1 => y = 4

y = 4/2 => y =2

so, all the values of x and y are correct.

if we put values of x given in other options and find value of y we cannot find whole table satisfying the equation.

hence option 1 is correct.

a and c

step-by-step explanation: