In two or more complete sentences, describe how to find the interval(s) where the function is decreasing and how interval notation is used to express the interval(s). in your final answer, include the interval in which the function is decreasing.

The interval in which the function is decreasing is:

                        (-5,0]

Step-by-step explanation:We know that for a linear function the function is decreasing if the graph is a straight line with negative slope i.e. the function is decreasing continuously.The function is a increasing function if the graph of the function is a straight line with positive slope i.e. the function is increasing continuouslyand the function is constant if the graph of the function is a straight horizontal line parallel to the x-axis.

From the graph we see that the function is increasing in the interval : [0,4]

and is decreasing in the interval : (-5,0]

and is constant in the interval: [-8,-5)∪[4,8)

Intersecting secant-tangent theorem states that if a tangent segment and a secant segment are drawn to a circle from an exterior point, then the square of the measure of the tangent segment is equal to the product of the measures of the secant segment and its external secant segment.so to break it down: 1. pq acts as the tangent and ps as the secant with an intersection at p.sr = 21rp = 3x + 3pq = 4x + 4following to equation: tangent squared = the two segments multiplied by each otherso (4x + 4) ^ 2 = (3x + 3) • (21) simplifies to 16x^2 - 31x - 47 = 0 or (16x - 47)(x + 1) x = -1 or x = 47/162. pq acts as the tangent and ps as the secant with an intersection at p (again! )sr = 16rp = xpq = 15(15) ^ 2 = 16 • x225 = 16xx = 225/163. the interesting chords are proportional to each other so a ratio is possible to set up: ap dp 10 3 + x = = —— = pc pb 8 xcross multiple to get 10x = (3 + x)(8)x = 12