What is the slope of the tangent line through (0,-3) and (x, y) for y = 3x2 - 3 and x=1?

First you must derive the equation to find the slope:
 y = 3x ^ 2 - 3
 y '= 6x
 Then, for x = 1 we have the slope is:
 y '(1) = 6 (1) = 6
 Then the equation of the line with slope equal to 6 and passing through point (0, -3) is:
 y = 6x - 3
 The slope is m = 6

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