What is the smallest of 3 consecutive positive integersif the product of the smaller two integers is 5 less than 5 times the largest integer

3 consecutive positive integers: x, x + 1, and x + 2

x(x+1) = 5(x+2) - 5
x^2 + x = 5x + 10 - 5
x^2 - 4x - 5 = 0
(x + 1)(x - 5) = 0
 x + 1 = 0; x = -1
 x - 5 = 0; x = 5
solutions are x = -1 and x = 5

However, consecutive positive integer only so x = 5 is the smallest positive integer here

answer
the smallest of 3 consecutive positive integers is 5