3. write the equation of a line that is perpendicular to the given line and that passes through the given point. y - 2 = 7/3 ( x + 5 ) ; ( -4 , 9) a. y - 9 = -3/7 ( x - 4) b. y - 9 = 3/7 ( x - 4) c. y - 9 = -3/7 ( x + 4) d. y - 9 = 3/7 ( x + 4)

To find the perpendicular line a y- 2 = 7/3 (x + 5) you must first observe that the slope is m = 7/3, therefore, the slope of the perpendicular line put of the reciprocal, that is, m = - 3/7. So the possible options are A or C, but since the point (-4, 9) must go through the line, we find that the equation that satisfies that is option C.Therefore the perpendicular line that passes through the point (-4, 9) is C. y - 9 = -3/7 (x + 4)