The angle of elevation to the top of a 10-story skyscraper is measured to be 3from a point on the ground 2,000 feet from the building. what is the height of the skyscraper to the nearest hundredth foot? a.285.09 feet b.104.67 feet c.66.58 feet d.104.82 feet

The correct option is D. 104.82 feet

Step-by-step explanation:

For better understanding of the solution see the attached figure of the problem :

Angle of elevation, θ = 3°

Distance between building and observing point = 2000 feet

⇒ BC = 2000 feet

To find : Height of the building, AB

Since, the building and the ground surface are perpendicular to each other

⇒ ΔABC is a right angle triangle right angled at B

Now, to find height of building using property of tan in ΔABC

Hence, The height of the building = 104.8 feet

Therefore, The correct option is D. 104.82 feet

$4

step-by-step explanation:

$30×5=$150

$150 minus $130=$20

$20÷5=$4.

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