(7a^5)/(b(b-1)(b+1))is undefined for all of the following, except for which value? a. a = 0 b. b = 1 c. b = –1 d. b = 0

The answer would be: A. a=0

The result of the equation would be undefined if the denominator is zero. In this question, the denominator is (b)(b-1)(b+1). You can find 3 results of variable b that will result in zero value of denominator.

(b)(b-1)(b+1)=0
1. b=0
2. b-1=0
    b=-1
3. b+1=0
    b=-1