Thomas solved the equation by completing the square. x2−10x+27=0 show work

Values of x will be [5 + √(-2)] and [5 - √(-2)]

Step-by-step explanation:

Thomas soled the equation (x² - 10x + 27) = 0 by completing the square.

x² - 2(5x) + 27 = 0

x² - 2(5x) + 25 - 25 + 27 = 0

(x - 5)² - 25 + 27 = 0

(x - 5)² + 2 = 0

(x - 5)² = - 2

(x - 5) = ±√(-2)

x = 5 ±√(-2)

Therefore, values of x will be [5 + √(-2)] and [5 - √(-2)].

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step-by-step explanation:

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