Which ordered pair makes both inequalities true? y > –3x + 3 y > 2x – 2 answer is (2,2)

Any ordered pair where x > 1 and y > 0 will work.

Step-by-step explanation:

First we will solve for x.  We will do this by eliminating the variable y, by subtracting the two inequalities:

 y > -3x+3

-(y > 2x-2)

y-y > -3x-2x+3--2

0 > -5x+5

Subtract 5 from each side:

0-5 > -5x+5-5

-5 > -5x

Divide each side by -5 (remember when you divide an inequality by a negative number you must flip the inequality symbol):

-5/-5 < -5x/-5

1 < x

This means x > 1.

Substituting 1 into the first inequality,

y > -3(1)+3

y > -3+3

y > 0

Any point with an x coordinate greater than 1 and a y coordinate greater than 0 will work.

answer: 177/8

step-by-step explanation: