Lindsey needs a jeweler to repair her earrings. jeweler a is offering her services for an initial $150 in addition to $14 per hour. jeweler b is offering his services for an initial $166 in addition to $12 per hour. when will the two jewelers charge the same amount of money?

A(X)=charge offered by jeweler A
x=number of hours.

A(x)=14x+150

B(x)=charge offered by jeweler B.
x=number of hours.

B(x)=12x+166

When the tow jewelers charge the same amount of money A(x) will be equal to B(x);
A(x)=B(x)

Therefore, we equalize both equations and solve them.

14x+150=12x+166
14x-12x=166-150
2x=16
x=16/2
x=8

jewelers´charge would be the same when they work 8  hours . 

Best answer that i found on yahoo ok   set :   x= length of 2nd piece in cm  x- 3= length of 1st piece in cm  x-4= length of 3rd piece in cm  then since you know they all came from the 20 cm ribbon you add them together and set them equal to 20x+ x-3 +x-4 = 20  3x - 7= 20  3x= 27  x= 9  the shortest piece is the third piece which is x- 4  x-4  9-4 = 5  the length of the smallest piece is 5 cm.  the other lengths are  9 cm  6 cm

Answer to your question: a. the fundamental theorem of algebra tells you that the equation will have two complex roots since the degree of the polynomial is 2. the roots are ​ x=1±i7√2 .number of roots=degree of polynomialhere, degree of polynomial is 2 so number of roots will be 2.hope it *_*