Mathematics, 29.07.2019 15:20 matthewquattlebum
Solve for x in the equation 2x^2+3x-7=x^2+5x+39
Answers: 2
![\mathrm{Apply\:radical\:rule}: \sqrt[n]{ab}=\sqrt[n]{a}\sqrt[n]{b} \ \textgreater \ \sqrt{47}\sqrt{2^2}](/tpl/images/0147/1120/edfb8.png)
![\mathrm{Apply\:radical\:rule}: \sqrt[n]{a^n}=a \ \textgreater \ \sqrt{2^2}=2 \ \textgreater \ 2\sqrt{47} \ \textgreater \ \frac{2+2\sqrt{47}}{2}](/tpl/images/0147/1120/f11a5.png)
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Solve for x in the equation 2x^2+3x-7=x^2+5x+39...
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