Line h contains the points (3,0) and (0,4). which point lies on a line that is perpendicular to line h and passes through point f (-6,-5)a) 3,0b)-3,1c) 6,4d) 6,2

(3,0)(0,4)
slope = (4 - 0) / (0 - 3) = -4/3
A perpendicular line will have a negative reciprocal slope. So our perpendicular line has a slope of 3/4

y = mx + b
slope(m) = 3/4
(-6,-5)x = -6 and y = -5
now sub into the formula and find b, the y int
-5 = 3/4(-6) + b
-5 = -18/4 + b
-5 + 18/4 = b
-20/4 + 18/4 = b
-2/4 = b
so ur perpendicular line is : y = 3/4x - 2/4or 3x - 4y = 2

and ur point (6,4) lies on the perpendicular line <===