Ascience teacher has a supply of 5% hydrochloric acid and a supply of 65% hydrocloric acid (hci). how much of each solution should the teacher mix together to get 42 ml of 45% hci for an experiment? a) the teacher will need 14 ml of the 5% solution and 28 ml of the 65% solution. b) 28 ml of 5% solution and 14 ml of the 65% solution c) 14 ml of the 5% and 14 ml of the 65% solution d) 28 ml of the 5% solution and 28 ml of the 65% solution

The teacher will need 14 ml of the 5% solution and 28 ml of the 65% solution.

Step-by-step explanation:

Since we have given that

There has a supply of 5% hydrochloric acid and a supply of 65% of hydrocholric acid.

The teacher needs to mix together to get 42 ml of 45% of hydrochloric acid for an experiment.

So, we will use "Mixture Allegation" to find the quantity of each solution,

Ist type of supply of HCL                 IInd type of supply of HCL

          5%                                                              65%

                                                  45%

----------------------------------------------------------------------------------------------

     65%-45%                                  :                      45%-5%

        20%                                        :                          40%

          2                                           :                           4

          1                                            :                            2

So, there is total quantity of mixture = 42 ml

So, Quantity of 5% solution will be

Quantity of 65% solution will be

Hence, the teacher will need 14 ml of the 5% solution and 28 ml of the 65% solution.

answer:  

123455421

step-by-step explanation: easy

r(0,90)(x,y) . t(-5,0)

last option

step-by-step explanation:

∆def to ∆d"e"f"

- rotate 90 counterclockwise degrees

- then translated 5 to the left (x --> x - 5)

answer is the last option