Determine the equations of the vertical and horizontal asymptote if any for g(x)= x-1/(2x+1)(x-5)

Horizontal asymptote : y = 0

Vertical asymptote :

2x+1 = 0, x-5 = 0

⇒

Step-by-step explanation:

Given :

Solution :

Case 1. When the degree of the denominator is larger than the degree of  the numerator), then the graph of y = f(x) will have a horizontal asymptote  at y = 0

Case 2 . the degrees of the numerator and denominator are the same then the graph of y = f(x) will have a horizontal asymptote at y =

Case 3 . the degree of the numerator is larger than the degree of the  denominator, then the graph of y = f(x) will have no horizontal asymptote.

Since in the given function degree of numerator is 1 and degree of denominator is 2 So, Case 1 applies here .

Thus Horizontal asymptote : y = 0

Vertical asymptote : for this we equate denominator = 0

2x+1 = 0, x-5 = 0

⇒

2.

according to newton’s cannonball model, what happens if the cannonball's velocity is enough to overpower the pull of earth’s gravitystep-by-step explanation:

answer:  

step-by-step explanation:

here x represents the height of the pole,

and, the height of the shadow of the pole is 12 feet.

also, the angle of elevation from the top of the pole is 40°,

therefore,

by the low of sine,

which is the required equation for finding the value of x,