How do i solve this order of operations

12

Step-by-step explanation: When you have a set of parentheses in an order of operations problem. you must simplify what's inside that set of parentheses first before you do anything else.

So our first step here is to subtract 64 - 16 which gives us 48.

So in our next step we have 48 ÷ 2².

The next thing to learn about the order of operations is that you must deal with exponents like the 2 in this problem before you can either multiply, divide, add, or subtract. So let's take a look at the exponent part of this problem, 2².

Remember than any number squared is that number times itself. So 2² is just 2 · 2 or 4. So our next step reads 48 ÷ 4 which simplifies to 12.

the first question mark is 6 and the second question mark is 26 (the square root)

step-by-step explanation:

simplifying

5(x + -6) = 2(x + 3)

reorder the terms:

5(-6 + x) = 2(x + 3)

(-6 * 5 + x * 5) = 2(x + 3)

(-30 + 5x) = 2(x + 3)

reorder the terms:

-30 + 5x = 2(3 + x)

-30 + 5x = (3 * 2 + x * 2)

-30 + 5x = (6 + 2x)

solving

-30 + 5x = 6 + 2x

solving for variable 'x'.

move all terms containing x to the left, all other terms to the right.

add '-2x' to each side of the equation.

-30 + 5x + -2x = 6 + 2x + -2x

combine like terms: 5x + -2x = 3x

-30 + 3x = 6 + 2x + -2x

combine like terms: 2x + -2x = 0

-30 + 3x = 6 + 0

-30 + 3x = 6

add '30' to each side of the equation.

-30 + 30 + 3x = 6 + 30

combine like terms: -30 + 30 = 0

0 + 3x = 6 + 30

3x = 6 + 30

combine like terms: 6 + 30 = 36

3x = 36

divide each side by '3'.

x = 12

simplifying

x = 12

this should .