Find three consecutive odd integers whose sum is 13 more than twice the largest of the three intergers

15,17,19 
Suppose the three odd integers are #n#, #n+2# and #n+4# 
Their sum is: 
#n + (n+2) + (n+4) = 3n+6# 
#13# more than twice the largest of the three is: 
#2(n+4)+13 = 2n+21# 
From what we are told these two are equal: 
#3n+6 = 2n+21# 
Subtract #2n+6# from both sides to get: 
#n = 15# 
So the three integers are: 
#15, 17, 19#