An alloy is 70% iron. how much of this alloy do you need if you want to obtain 50 7/20 lb of iron?

72 lb

Step-by-step explanation:

An alloy is 70% iron, that is, there are 70 lb or iron every 100 lb of the alloy. This is our conversion factor. In order to find out how much allow is required to obtain 50 7/20 lb (50.35 lb) of iron, we will use proportions.

50.35 lb iron × (100 lb alloy/70 lb iron) = 72 lb alloy

We will need 72 lb of the alloy.

1. sometimes

2.   never

3   .08c = 7.50+.05c   250 pages

step-by-step explanation:

1.   sometimes

the theoretical probability of rolling a 1 is 1/6.   perhaps you got really lucky and never rolled a 1   in those 60 times.   your experimental probability is 0.   or perhaps you rolled a 1   20 times.   your experimental probability is 20/60 is 1/3.     it really just depends on how you rolled in that experiment.

2.   never

the probability of the event occurring is 1.   that is being 100 % sure it will happen.   that is the maximum amount of confidence we have.

3.   no customer card cost:   .08 times number of pages

customer card cost:   7.50 + .05 times number of pages

we want to find when it costs the same amount, so we will set these equal

let c = number of pages

.08c = 7.50+.05c

subtract .05c from each side

.08c-.05c = 7.5+.05c-.05c

.03c=7.5

divide each side by .03

.03c/.03 = 7.5/03

c =250  

the cost is the same at 250 pages

a orange at the grocery store idk what other product that could be