Agent hunt is transferring classified files from the cia mainframe into his flash drive. s(t) models the size of the files on the drive (in megabytes) after t seconds. s(t)=5t+45. what was the file size on the drive before the transfer? answer in megabytes.

50 megabytes every 10 seconds

Step-by-step explanation:

The rate of change of the equation is 5 megabytes per second. To find the number of megabytes Agent Hunt transfers, we can multiply the rate of change by 10, the transfer time in seconds.

5 megabytes/seconds * 10 seconds = 50 megabytes

The seconds cut and then you multiply 5 with 10 = 50 megabytes

I hope it helped :)

no

step-by-step explanation:

2-7=-5

7-2=5

when you combing like terms for ech expression, 5 and -5. these numbers are not equal to each other.

answer: the price of one pound cabbage = $ 0.8

the point (10,8) represents that the cost of 10 pounds cabbage is $ 8

step-by-step explanation:

since, here is a proportional relation between the number of pounds of cabbage (x) and the price in dollars (y).

therefore, we can write,

⇒ y = k x

where k is the constant of proportionality.

now, point (5,4) is in the line.

thus, it will satisfies the above equation of line.

⇒ 4 = 5 k

⇒ k = 0.8

thus, the equation of the line is,

y = 0.8 x

a) for x = 1,

y = 0.8

therefore, the cost of one pound of cabbage is 0.8 dollars.

b) in the below graph (10,8) represents that the cost of 10 pounds of cabbage is 8 dollars.