1. find the slope of the line. (picture attached)

a. -4
b. -1/4
c. 1/4
d. 4

2. what is the slope of the line that passes through the pair of points (-5.2, 8.7) and (-3.2, 2.7)?

a. 2
b. 3
c. -2
d. -3

3. the table shows the height of a plant as it grows. which equation in point-slope form gives the plant’s height at any time. (picture attached)

a. y+18=9(x+2)
b. y-18=9x+2
c. y-18=9(x-2)
d. the relationship is nonlinear.

1. The answer would be 1/4To find the slope, you use this formula:slope: y1-y2/x1-x2You need to determine two points. In this case, let use the point where y=0 and y=1 which was x1, y1= (-4,0)  and x2, y2= (0,1)
The calculation would be:slope: y1-y2/x1-x2slope: (1-0)/ (0- -4)= 1/4

2. The answer would be: -3
There is 2 different coordinate in this question which was:
x1,y1= (-5.2, 8.7)
x2,y2=(-3.2, 2.7)

Using the same slope formula, you can get this equation
slope: y1-y2/x1-x2slope: 8.7-2.7/(-5.2) - (-3.2)slope: 6/-2slope= -3

3. The answer is: C. Y-18=9(x-2)
Let say that the plant height is in Y-axis and the month in X-axis. Then you can get 4 coordinate, but we just need two. The list of coordinate would be:
x1,y1= (2, 18)
x2,y2=(4, 36)
Using the slope formula you can get the m variable for point-slope form
slope: y1-y2/x1-x2slope: 18-36/2-4slope: -18/-2= 9

Since the slope is 9 (m=9), the point-slope form would be:
y-y1=m(x-x1)
y-18= 9(x-2)

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