Angle $eab$ is a right angle, and $be = 9$ units. what is the number of square units in the sum of the areas of the two squares $abcd$ and $aefg$?

Let the measure of side AB be x, then, the measue of side AE is given by

.

Now, ABCD is a square of size x, thus the area of square ABCD is given by



Also, AEFG is a square of size , thus, the area of square AEFG is given by



The sum of the areas of the two squares ABCD and AEFG is given by



Therefore, the number of square units in the sum of the areas of the two squares ABCD and AEFG is 81 square units.

The answer is “faster”.