Solve the following system of equations. -3/4x + 1/2y = -2 1/5x - 1/4y = -6 x = ? y = ?

There are various ways to solve this. I will solve by elimination which seems easier:
I multiply the top equation by 1/2 to get 1/4y so I can eliminate y:
-3x/8 + 1y/4 = -1 Now add the second equation:
1x/5 - 1y/4 = -6 This gives:

-3x/8 + 1x/5 = -7 Get a common denominator:
-15x/40 + 8x/40 = -7 Now add fractions:
-7x/40 = -7 Multiply by the reciprocal(-40/7):
x = 7 × 40 / 7 Simplify:
x = 40.
Now plug in 40 for x in one of the equations and solve for y (2nd equation looks easier):
1(40)/5 - 1y/4 = -6
8 - y/4 = -6 subtract 8
-y/4 = -14 multiply by 4
-y = -56
y = 56.

So we got x=40 and y=(56) new lets check!
-3(40)/4 + (56)/2 = -2
-3(10) + 28 = -2
-30 + 28 = -2
-2 = -2.

The answer should be c.