Me? ? what is 727−−√+548−−√ in simplified radical form?

7√27 + 5√48 in simple radical form

41 sqrt(3)

√27 can be written as √(3*3^2) = 3√3

√48 can be written as √(3*4^2) = 4√3

so 7√27 + 5√48 = 7*3√3 + 5*4√3 = 21√3 + 20√3 = 41√3

41√3 will be the simplified radical form of given expression.

Explanation:

Since, Given expression is 7√27+5√48

= 7×√9×√3+ 5 × √16×√3  (because, √(m×n)=√m×√n)

= 7×3×√3+5 × 4×√3 ( because, √9=3 and √16=4)

= 21√3+20√3  (because m×√n=m√n)

= (21+20)√3 ( by associative property under multiplication over addition)

=41√3. (by addition)

⇒7√27+5√48=41√3

Thus, the simplified form of 7√27+5√48 is 41√3.

i dont know sorry

step-by-step explanation:

17.08

correct me if i am wrong.