Mathematics, 26.07.2019 21:40 ashiteru123
Ineed solving this trig problem w/ identites. (1)/(sinx-1)+(1)/(sinx+1) a. 2cot^(2)xsecx b. sec^(2)xcsc^(2)x c. secxcosx d. 2sec^(2)x
Answers: 1
![\bf \cfrac{1}{sin(x)-1}+\cfrac{1}{sin(x)+1}\implies \cfrac{sin(x)+1~~+~~sin(x)-1}{[sin(x)-1][sin(x)+1]} \\\\\\ \cfrac{2sin(x)}{\stackrel{\textit{difference of squares}}{sin^2(x)-1^2}}\implies \cfrac{2sin(x)}{sin^2(x)-1}\implies \cfrac{2sin(x)}{-[~1-sin^2(x)~]} \\\\\\ \cfrac{2sin(x)}{-[cos^2(x)]}\implies -2\cdot \cfrac{sin(x)}{cos(x)}\cdot \cfrac{1}{cos(x)}\implies -2tan(x)sec(x)](/tpl/images/0136/4155/cab09.png)
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Ineed solving this trig problem w/ identites. (1)/(sinx-1)+(1)/(sinx+1) a. 2cot^(2)xsecx b. sec^(2...
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