Arectangular solid (with a square base) has a surface area of 73.5 square centimeters. find the dimensions that will result in a solid with maximum volume

The solution for this problem is:
The only given here is the volume which is equal to 73.5 square centimeters.
Maximum volume occurs when the solid is perfect cube.
6x^2 = 73.5 sq cm
x^2 = 73.5 / 6
x^2 = 12.25
x = √12.25
x = 3.500
x = 3.5 cm length x 3.5 width x 3.5 height

A) for the n row: 22+(n-1)×6therefore,b) 100-22=78that means (n-1)×6=7878÷6=1313+1=1414th row has 100 seats