Given that lines a and b are parallel and that m∠6 = 74°, find m∠1

m∠1 = 106°

Step-by-step explanation:

Here the lines "a" and "b" are parallel and m∠6 = 74°.

We need to find m∠1 .

It is clearly know that from the given information, two parallel lines "a" and "b" cut by a transversal line.

I have attached the figure here. Please have a look at it.

From the figure ∠1 and ∠6 are inside adjacent angles. They add upto 180 degrees.

Therefore, m∠1 + m∠6 = 180°

Given: m∠6 = 74°

So, 74° + m∠1 = 180°

Subtracting 74° from both sides, we get

74° - 74° + m∠1 = 180° - 74°

m∠1 = 106°

(n^3 - n)

= n(n-1)(n+1)

since it is divisible by 3 and 2 ,because it is a multiple 3 consecutive number

if, n-1 is odd then n+1 is also odd, then it is a multiple of 9

but if, n-1 is even then n+1 is also even, then it is a multiple of 4

so, largest multiple = max(9*2, 4*3) = max(18, 12) = 18