Evaluate yds where s is the portion of the cylinder x^2+y^2=3 that lies between the planes z = 0 and z = 3

Unsure of what you mean by "yds."  Sounds like you're interested in the volume of this portion of the cylinder.

The cyl. is a vertical one, with the z-axis as its axis.  The radius of a horiz. cross section is sqrt(3), and the height of the cyl. is 3.

Thus, the volume is V = pi*r^2*h, which here is pi*[sqrt(3)]^2*3, or 9 pi.

If this is not what you had in mind, please add to your problem description so that your goal becomes clearer.

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