Identify the y-intercept 1.)v^2 - 11v+30=0 2.) v^2 + 2v - 8=0

We know that y-intercepts are the values found when x=0; 

1) v²-11v+30=y <-- replace 0 as y and substitute x=0
(0)²-11(0)+30=y 
30=y 

The y-intercept is 30 here. 

2) v²+2v-8=y <-- repeat the above steps 
(0)²+2(0)-8=y 
-8=y 

The y-intercept is -8 here 

As you can notice, the c value in the standard equation (ax²+bx+c=y) is the y-intercept. 

Hope I helped :) 

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