Rectangle j'k'l'm' shown on the grid is the image of rectangle jklm after transformation. the same transformation will be applied on trapezoid stuv, as shown below: rectangle jklm is drawn on the grid with vertices j at negative 5, 1. k is at negative 5, 6. l is at negative 7, 6. m is at negative 7, 1. rectangle j prime k prime l prime m prime is drawn with vertices at j prime 4, 4. k prime is at 4, 9. l prime is at 2, 9. m prime is at 2, 4. trapezoid stuv is drawn with vertices at s is at 9, negative 6. t is at 9, negative 2. u is at 7, negative 2. v is at 6, negative 5. what will be the location of u' in the image trapezoid s't'u'v'? (16, −2) (14, −2) (14, 1) (16, 1)

Location U' in the image trapezoid will be (16, 1)

Step-by-step explanation:

Rectangle JKLM has been transformed to J'K'L'M'. So changed vertices of JKLM will become as

J(-5,1) → J'(4, 4)

K(5, 6) → K'(4, 9)

L(-7, 6) → L'(2, 9)) Transformation done was shifting of L to L' by (9, 3) [2-(-7)=9, 9-6=3]

M(-7, 1) → M'(2, 4)

Now we have find the find the transformed vertex U' by using the same transformation rule done in L → L'

Since coordinates of U are (7, -2), we will transform is to get get U'

x coordinates = 7 + 9 = 16

y coordinates = -2 + 3 = 1

So U' will be (16, 1).

sinn is the total amount of students now and m were the students before, you subtract them both (n-m) and divide that by m. then, since to get a percentage from a fraction you have to multiply by 100, your answer should look like this: n-m/m*100

step-by-step explanation:

in mathematics, a constraint is a condition of an optimization problem that the solution must satisfy. there are several types of constraints—primarily equality constraints, inequality constraints, and integer constraints. the set of candidate solutions that satisfy all constraints is called the feasible set.

hoped i'm right lol