Given that the values in the table represent the graph of a continuous function, y has at least how many zeros? x y –3.0 8.40 –2.4 0.69 –1.8 –0.39 –1.2 0.24 –0.6 0.46 0 0 0.6 –0.46 1.2 –0.24 1.8 0.39 2.4 –0.69 3.0 –8.40 3 4 5 6

To find the number of zeroes of a curve , we have to find how many times the curve crosses or cuts the X axis.

The given (x,y) values are :x y (–3.0, 8.40) (–2.4 ,0.69) (–1.8 ,–0.39) (–1.2 ,0.24) (–0.6 ,0.46) (0, 0) (0.6 ,–0.46) (1.2 ,–0.24) (1.8 ,0.39) (2.4 ,–0.69) (3.0 ,–8.40)

It means the curve passes through these points.Plot these points in two dimensional coordinate plane.

OR

By putting the points on Graphing Calculator , we can find how many Zeroes does y have or how many times it crosses the X axis.

First ordered pair lies in second quadrant, Then the third ordered pair lies in third quadrant, then the coming ordered pair  lies in second quadrant, then passes through the origin, then the  next ordered pair lies in fourth quadrant, then in first quadrant, then in fourth quadrant.→→→→By looking at the ordered pairs

As you can see without the help of graph, the line joining between two points crosses the X axis 5 times.

So, Maximum number of Zeroes = 5→→Option (C)

d. vertex

step-by-step explanation:

2.2°  

step-by-step explanation:

let θ = the angle of elevation.

tanθ =77/2020

tanθ = 0.038 12

      θ = tan⁻¹0.038 12

      θ = 2.2°