Rainer bought 1.43 pounds of lunch meat at the store for 10.98.what was the unit rate (price) of the lunch meat?

Answer : The unit rate (price) of the lunch meat was, $7.68

Step-by-step explanation :

As we are given that the rainer bought 1.43 pounds of lunch meat at the store for $10.98.

Now we have to determine the unit rate (price) of the lunch meat.

As, the rate of lunch meat of 1.43 pounds = $10.98

So, the rate of lunch meat of 1 pounds =

                                                                = $7.68

Thus, the unit rate (price) of the lunch meat was, $7.68

7.9m and 4.3°

step-by-step explanation:

let east be +x and north be +y, x = distance * cos θ, y = distance * sin θ  

for 3.5 south, y = -3.5  

for 8.2, x = 8.2 * cos 30 and y = 8.2 * sin 30  

for 15 west, x = -15  

total x = 8.2 * cos 30 – 15 ≈ -7.9  

total y = -3.5 + 8.2 * sin 30 = 0.6  

magnitude = [(8.2 * cos 30 – 15)^2 + 0.6^2)]^0.5  

the magnitude is approximately 7.9 m  

tan θ = y/x = 0.6/-7.9  

the angle is approximately 4.3˚ north of west