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Mathematics, 24.07.2019 08:50 xelynncaldera
What is the 8th term in the sequence? an=25β3n enter your answer in the box.
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Which statement explains how you could use coordinate geometry to prove that quadrilateral abcd is a parallelogram? -5 -4 -3 -2 -1 t 1 2 3 4 prove that all sides are congruent and have slopes that are opposite reciprocals prove that segments ad and ab are congruent and parallel prove that opposite sides are congruent and have equal slopes prove that segments bc and cd are congruent and parallel
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Mathematics, 22.06.2019 02:30
Nicolo paganini's numbers 1184 and 1210 are amicable. the proper divisors of 1184 are 1, 2, 4, 8, 16, 32, 37, 74, 148, 296, and 592. the proper divisors of 1210 are 1, 2, 5, 10, 11, 22, 55, 110, 121, 242, and 605. use the definition of amicable (friendly) numbers to show that they are indeed amicable. which of the folowing statement uses the definition of amicable numbers to show that 1184 and 1210 are indeed amicable? o a. o b. Β° c. the sum of proper divisors of 1184 is 1210 and the sum of proper divisors of 1210 is 1184 the sum of proper divisors of 1184 is greater than 1210 and the sum of proper divisors of 1210 is greater than 1184 the sum of proper divisors of 1184 is less than 1210 and the sum of proper divisors of 1210 is less than 1184
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Mathematics, 22.06.2019 03:00
A. find the power of the test, when the null hypothesis assumes a population mean of mu = 450, with a population standard deviation of 156, the sample size is 5 and the true mean is 638.47 with confidence intervals of 95 b. find the power of the test, when the null hypothesis assumes a population mean of mu = 644, with a population standard deviation of 174, the sample size is 3 and the true mean is 744.04 with confidence intervals of 95% c. find the power of the test, when the null hypothesis assumes a population mean of mu = 510, with a population standard deviation of 126, the sample size is 10 and the true mean is 529.44 with confidence intervals of 95
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What is the 8th term in the sequence? an=25β3n enter your answer in the box....
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